Determine the point estimate of the population proportion, the margin of error f

Question

Determine the point estimate of the population proportion, the margin of error for the following confidence interval, and the number of individuals in the sample with the specified characteristic, x, for the sample size provided Lower bound:0 691, upper bound:0 899 n= 1200 The point estimate of the population proportion is! Round to the nearest thousandth as needed) The margin of error is Round to the nearest thousandth as needed) The number of individuals in the sample with the specified characteristic is Round to the nearest integer as needed.) Enter your answer in each of the answer baxes

Explanation / Answer

Solution

(a) point estimate = (lower bound + upperbound)/2 = (0.691+0.899)/2 = 0.795

(b) Margin of error = (Upper bound - loer bound)/2 = (0.899-0.691)/2 = 0.104

(c) 0.795-z*margin of error = 0.691

z value = +-1

((0.795)(1-0.795)/n)0.5 = 0.104

n = 15

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