A0.01 significance level is used for a hypothesis test of the claim that when pa

Question

A0.01 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender selection, the proportion of baby girls is less than 0.5. Assume that sample data consists of 66 girls in 144 births, so the sample statistic of a results in az score that is 1 standard deviation below 0. Complete parts (a) through (h) below. Click here to view page 1 of the Normal table. Click here to view page 2 of the Normal table. a. Identify the null hypothesis and the alternative hypothesis. Choose the correct answer below. OB. Ho: p#0.5 H:p0.5 OA. Ho: p=0.5 H:p* 0.5 OC. Ho: p=0.5 Hy:p

Explanation / Answer

Given that,
possibile chances (x)=66
sample size(n)=144
success rate ( p )= x/n = 0.4583
success probability,( po )=0.5
failure probability,( qo) = 0.5
null, Ho:p=0.5  
alternate, H1: p<0.5
level of significance, = 0.03
from standard normal table,left tailed z /2 =1.88
since our test is left-tailed
reject Ho, if zo < -1.88
we use test statistic z proportion = p-po/sqrt(poqo/n)
zo=0.45833-0.5/(sqrt(0.25)/144)
zo =-1
| zo | =1
critical value
the value of |z | at los 0.03% is 1.88
we got |zo| =1 & | z | =1.88
make decision
hence value of |zo | < | z | and here we do not reject Ho
p-value: left tail - Ha : ( p < -1 ) = 0.15866
hence value of p0.03 < 0.15866,here we do not reject Ho
ANSWERS
---------------
null, Ho:p=0.5
alternate, H1: p<0.5
alpha = 0.03
normal distribution
test statistic: -1
critical value: -1.88
decision: do not reject Ho
p-value: 0.1587
no evidence that proportion of gisls are less than 50%

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