Let x be a random variable that represents assembly times for the Ford Taurus. T

Question

Let x be a random variable that represents assembly times for the Ford Taurus. The Wall Street Journal procedure has been made. Experience wth this new method indicates that -0.9 new Ford Taurus automobiles coming off the assembly line showed reduced? Use -0.01. (Use 2 decimal places for the test statistic and test statistic critical value reported that the average assembly time is u 38 hours. A modification to the assembly hours. It is mought that the average assembly time may be reduced by this modiation. A random sample of 47 the average assembly time of the new method to be x 37.80 hours. Does this indicate that the average assembly time has been the critical value, use 4 dedmal places for the Avalue P-value Reject the null hypothesis, thero is sumient evidence that -average assembly time is less than 38 hours. Reject the null hypothesis, there is insufficient evidence that the average assembly time is less than 38 hours Faa to reject the null hypothesis, there is sufficient evidence that the O Fad to repect the nu hypothesis, there is nsumoent evidence that the average assembly time is less than 38 hours average assembly time is less than 38 hours

Explanation / Answer

Hypothesis:

Ho : µ = 38

vs

H1 : µ < 38

µ = 38

= 0.9

X bar = 37.80

n= 47

alpha = 0.01

Test statistic :

Z = (37.80-38) / (0.9/470.5) = -1.52348

Critical value :

Z 0.01 = -2.3263

P-value : 0.0643

Conclusion :

P-value > alpha

Fail to reject the null hypothesis, there is insufficient evidence that the average assembly time is less than 38 hours.

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