Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

This Question: 4 pts 2 of 25 (16 complete) This Test: 100 pts possible It the 19

ID: 3325624 • Letter: T

Question

This Question: 4 pts 2 of 25 (16 complete) This Test: 100 pts possible It the 1980s it was generally believed that congenital abnormalities affected about 7% of a large nation's children. Some people believe that the increase in the number of chemicals in the environment has led to an increase in the incidence of abnormalities. A recent study examined 408 randomly selected children and found that 29 of them showed signs of an abnormality. Is this strong evidence that the risk has increased? (We consider a P-value of around 5% to represent reasonable evidence ) Complete parts a through a) Write appropriate hypotheses. Let p be the proportion of children with genetic abnormalities. Choose the correct answer below. O B. Ho-p:0.07 vs. HA, p#0.07 0 D. Ho-p:0.0711 vs. HA: p#00711 O F. Ho p 0.0711 vs. HA p 0.0711 OA. Ho p 0.0711 vs. HA p 0.0711 O C. Hop 0.07 vs. HA p 0.07 OE. Ho:p=0.07 vs. HA: pc 0.07 b) Check the necessary assumptions. Which of the following are satisfied? Select all that apply A. The data are independent B. There are more than 10 successes and 10 failures. C. Less than 10% of the population was sampled. D. The sample is random. c) Compute the test statistic. (Round to two decimal places as needed.) Find the P-value Click to select your answers).

Explanation / Answer

A) Option-C

B) Option-A

C) p = 29/408 = 0.0711

The test statistic Z = (p - P)/sqrt(P (1 - P)/n)

= (0.0711 - 0.07)/sqrt (0.07 * 0.93/408)

= 0.09

P-VALUE = P(Z > 0.09)

= 1 - P(Z < 0.09)

= 1 - 0.5359 = 0.4641

D) Option-C

E) Option-c

F) Option-B

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote