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ichColegeCUNYFrst Login PortalLogin B Baruchmal BBCTC. Baruch Calle B Newman tony Blanhalenan Assignment . Responses last?dep 175 14911 a04 There are 45 students in an elementary statistics dass. On the basis of years of experience, the instructor knows that the time needed to grade a randomly chosen first examination paper is a random variable with an expected value of 5 min and a standard deviation of 4 min. (Round your answers to four decimal places.) (a) If orading times are independent and the instructor begins orading at 6:50 PM. and orades continuously, what is the (aperoxlmute) protuabilily that he i trough orading bafore the 11.00 RK. TV news begins? 93160499x (b) If the sports report begins at 11:10, what is the probability that he misses part of the report if the waits until grading is dore before turning on the TV? You may need to use the appropriate table in the Appendix of Tables to answer this question. 9trnt Amwei Save Progress : Prance Another verson Time takken by a randomly selected applicant for a mortgage to fill out a certain form has a normal distribution with mean value 9 min and standard deviation 2 min five individuals fillout a form on one day and six on another, what is the probability that the sample average amount of time taken on each day is at most 11 min? (Round your answer to four decimal places) 0 9803 You may need to use the appropriate table in the Appendix of Tables to answer this question. Need Help? LhH.. Lse".MI 12 points Rockowell hardness of pins of a certain type 4Round your anewers to four dedimal places is known to have a mean value of 50 and a standard deviation of that the sample mean handness for a andom sample of 0 pins is at east s1 a) If the distributiorn 10 8Explanation / Answer
Solution:- There are 45 students.The expected value 5 min and standard deviation 4
=> n = 45 , = 5 , = 4
There fore
T = n = 5*45 = 225 min
T = sqrt(n) = 4sqrt(45) = 26.8328 min
a) 6:50pm to 11:00pm = 240+10 = 250 min
P(T < 250) = P(Z < (250-225)/26.8328)
= P(Z < 0.9317)
= 0.8238
b) P(T > 260) = P(Z > (260-225)/26.8328)
= P(Z > 1.3044)
= 1 P(Z < 1.3044)
= 1 0.9032
= 0.0968
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