D× c se ure https://www.mathx.com/Student PlayerTest.aspx canvas asi. D a Statis
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D× c se ure https://www.mathx.com/Student PlayerTest.aspx canvas asi. D a Statistics for Decision-Making Submit Q Time Remaining: 01:48:06 Quiz: Week 7 Quiz This Quiz: 60 pts poss 1 of 19 (0 complete) This Question: 4 pts In a survey of 633 males ages 18-64, 397 say they have gone to the dentist in the past year Construct 90% and 95% confidence intervals for the population proportion Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals The 90% confidence interval for the population proportion p s (Round to three decimal places as needed ) CD The 95% confidence interval for the population proportion p is OD (Round to three decimal places as needed ) Interpret your results of both confidence intervals O A. With the given confidence,it can be said that the population proportion of males ages 18-64 who say they have gone to the dentist in the past year is not between the endpoints of the given confidence interval to the dentist in the past year is between the endpoints of the given confidence interval fidence, it can be said that the population proportion of males ages 18-64 who say they have gone O c. With the given confidence, it can be said that the sample proportion of males ages 18-64 who say they have gone to the dentist in the past year is between the endpoints of the given confidence interval. Which interval is wider? O The 90% conidence interval The 95% confidence interval O Click to select your answer(s). Type here to searchExplanation / Answer
Solution:- Given n = 633 , X = 397
p = 397/633 = 0.627 , q = 1 - p = 1 - 0.627 = 0.373
90% confidence interval for Z is 1.645
95% confidence interval for Z is 1.96
=> The 90% confidence interval for the population proportion p is (0.595 , 0.659)
=> p +/- Z * sqrt(pq/n)
= 0.627 +/- 1.645 * sqrt(0.627*0.373/633)
= (0.595 , 0.659)
=> The 95% confidence interval for the population proportion p is (0.589 , 0.665)
=> p +/- Z * sqrt(pq/n)
= 0.627 +/- 1.96 * sqrt(0.627*0.373/633)
= (0.589 , 0.665)
=> option B.
=> option B. The 95% confidence interval
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