Question 8- of 1 5 Step 7 of 10 00:59:49 SeQun, which is used for treating kidne

Question

Question 8- of 1 5 Step 7 of 10 00:59:49 SeQun, which is used for treating kidney disease, has been found to have the following side effects in systolic blood pressure in patients: 20 % have at least a 5 % increase, 10 % have less than a 5 % change, and 70 % have at least a 5 % decrease. A new drug for treating kidney disease is being tested. A study of 240 patients using the new drug is conducted. Can it be concluded that there is a difference in systolic blood pressure side effects between SeQuix and the new drug? Side effect Number of Patients at least 5 % increase less than 5 % change at least 5 % decrease 46 139 Copy Data Step 7 of 10: Find the degrees of freedom associated with the test statistic for this problem. Answer/How to Enter) 2 Points Keypad Tab

Explanation / Answer

observed frequncies are Oi

55 46 139   

------------------------------------------------------------------

expected frequencies are Ei

20% of 240 = 48

10% of 240 = 24

70% of 240 = 168   

------------------------------------------------------------------

and claiming hypothesis is

null, Ho: no association exists b/w them OR observations are independent

alternative, H1: exists association b/w them OR observations are dependnet

level of significance, = 0.05

from standard normal table, chi square value at right tailed, ^2 /2 =5.9915

since our test is right tailed,reject Ho when ^2 o > 5.9915

we use test statistic ^2 o = (Oi-Ei)^2/Ei

from the table take sum of (Oi-Ei)^2/Ei, we get ^2 o = 26.1935

critical value

the value of |^2 | at los 0.05 with d.f, n - 1 = 3 - 1 = 2 is 5.9915

we got | ^2| =26.1935 & | ^2 | =5.9915

make decision

hence value of | ^2 o | > | ^2 | and here we reject Ho

^2 p_value =0

ANSWERS

---------------

null, Ho: no association exists b/w them OR observations are independent

alternative, H1: exists association b/w them OR observations are dependnet

test statistic: 26.1935

critical value: 5.9915

p-value:0

decision: reject Ho

degrees of freedom = n - 1 = 3 -1 = 2

Observed (Oi ) Expected ( Ei) Oi-Ei (Oi-Ei)^2 (Oi-Ei)^2/Ei 55 48 7 49 1.0208 46 24 22 484 20.1667 139 168 -29 841 5.006

Related Questions

Navigate

• Browse (All)
• Browse Q
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.