MATH 1680 ELEMENTARY PROBABILITY AND STATISTICS EXAM 2 (SECOND ATTEMPT5 3A. In a
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MATH 1680 ELEMENTARY PROBABILITY AND STATISTICS EXAM 2 (SECOND ATTEMPT5 3A. In a sample of 567 randomly selected students, 245 faxored the amount being budgeted for next year's intramural and interscholastic sports. (a) What is the best point estimate of the proportion of the students who favor th year's budget on intramural and interscholastic sports? (6 points) e next (b) For the interval estimate of the proportion, which curve/table is appropriate, : or th Be sure to justify your response. (5 points) (c) Find the 98% upper confidence bound of the true proportion of the students who favor the nest year's budget on intramural and interscholastic sports. Be sure to justify all steps graphically and analytically. (10 points)Explanation / Answer
3.
a) Point estimate = 248/567 = 0.437389771
p = 0.4374
b)
As the sample size is sufficiently large we use z curve/table
c)
n 567 p 0.437389771 z-value of 98% CI 2.3263 SE = sqrt(p*(1-p)/n) 0.02083 ME = z*SE 0.04846 Lower Limit = p - ME 0.38893 Upper Limit = p + ME 0.48585 98% CI (0.3889 , 0.4859 )Related Questions
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