Whole question please. Random Sample size = 10 Standard Deviation = 2.1 lb Weigh

Question

Whole question please.

Random Sample size = 10

Standard Deviation = 2.1 lb

Weight mean =21.4

PARTL:PROBLEMS: KINDLY COMPLETEALL PARTS OF AUL PROLANS PARANNIT WILL BE GIVEN ON THE PARIS 01THE PROBLEMs rMAT uKECMreSTn. 1. In a forging factory the required weight of a frged tonsnission's pun rawe than 20 Lbs. in order to be accepted and used in the car asssenbly of the nshisss. e s pans' weights are known to have a nomal distribution. A randem smpe e1e pes wos silsssi om forging factory and fournd that is mean of pans' weight oqualsas24lts wilh a sunissiih el 2.1 Lbs. Use 0.025. Does the data int is sample meet the rourements ofthetran ens son sat ohev wth hisGMw Perform a Hypothesis test; list all the required S stups in order ts atswor the asiso is normal plot. DO NOT uss the Lthe Centleisess biecsl A. Repeat only the three required steps to test the same Hypothesis as in part A but uNe ONLY the YALUE as a reiection rule (9 Points)

Explanation / Answer

1) Traditional test hypothesis or critical value method

H0 : u = 20.1

H1 : u > 20.1

Decision rule : If T statistic > 2.262 then reject H0

T statistic = xbar - µ /(s/n)

                 = 21.4 - 20.1 / [2.1/(10)]

= 1.96

Here T statistic = 1.96 < 2.262, So Do not reject H0

we conclude that there is no sufficient evidence that the true mean is greater than 20.1

2) p value method

Decision rule : If p value < 0.025, then reject H0

p value = p [t > 1.96] = 0.0408

here p value = 0.0408 > 0.025

Do not reject H0

we conclude that there is no sufficient evidence that the true mean is greater than 20.1

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