(4 points) Suppose a company that sells hamburger patties finds that the mean we

Question

(4 points) Suppose a company that sells hamburger patties finds that the mean weight of their patties is 3.65 ounces with a standard deviation of 0.44 ounces. The company plans to selecta sample of 16 patties. Standard Deviation of Sampling Distribution: Mean of Sampling I 4 points) A pollster wants to determine the outcome of an upcoming election. In order to deter- ine the true proportion of people planning to vote for each candidate with a margin of error that less than 5% , how many people should be sampled using a 90% level of confidence?

Explanation / Answer

Mean of sampling distribution = 3.65

Standard deviation of sampling distribution = 0.44/sqrt(16) = 0.11

At 90% Confidence interval the critical value is z0.05 = 1.645

Margin of error = 0.05

Z0.05 * SD/sqrt (n) = 0.05

Or, 1.645 * 0.44/sqrt(n) = 0.05

Or, sqrt(n) = 1.645 * 0.44/0.05

Or, sqrt (n ) = 14.476

Or, n = 210

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