given, ente 2- Samp I1nts needed Test An economist believes that the percentage
ID: 3324199 • Letter: G
Question
given, ente 2- Samp I1nts needed Test An economist believes that the percentage than the percentage of rural households with urban households and finds that 707 of them have Internet rural households and finds that 647 of the have Interne ce cae type of test should be used in this 8. Wihat shoulá we Internet access He lain at the a-0.11 and finds that 647 of them have Internet sccess search? A. One-sample t-test B. One-sample proportion z-test C. Two-sample Proportion z-test D. Two-independent sample z-test E. Two-independent sample t-test. A. Cannot reject the al hyothess B. Accept the null bhypodesis C. Reject the null hypothesis D. Reject the alternative hypotbesis 39, At -0, 11, what is the research conclusion . Is it a one-tailed or two-tailed test? A. There is insufficient evidence to conchule A. Two-tailed and right-tailed B. Two-tailed and left-tailed C. Two-tailed D. Left-tailed that the internet access rate in the uban area is greater than the internet accessa in the rural area B. There is sufficient evidence to conchude E. Right-tailed. What will be the research hypotheses? that the internet access rate in the urban area is greater than the internet access raie in the rural area C. There is sufficient evidence to conclude vS that the internet access rate in the rural area is not greater than the internet access rate in the urban area D. There is insufficient evidence to conclude that the internet access rate in the rural area is not greater than the internet acce rate in the urban area. Vhat is the critical value in the research? 40. Compute the upper boundary of the 89% for the estimated population proportion 1.5945 1.4718 . 1.3492 1.2265. difference A. 0.3337 B. 0.1593 C. 0.0822 hat is the test statistic in the research? 0.6878 1.2481 2.2648 4.1097 7.4574. D. 0.0481 E. 0.0330Explanation / Answer
33. option C.
Two sample proportion z test.
There are two samples and we have to test about the population proportion.
34. Option E.
It is right tailed test. because the critical region is on the right side.
35. Option A.
Ho: Pu = Pr
vs
H1: Pu > Pr
36.
Pooled sample proportion = Pp = (707+647) / (800+750) = 0.8735
pu =707/800 =
0.88375
pr =647/750=
0.862667
pu-pr =
0.021083
sqrt {Pp (1-Pp) }
=
0.332412
1/nu = 1/800 =
0.00125
1/nr = 1/750=
0.001333
Z statistic =
0.021083
0.050827
= 1.247
is approximately equals to option E. that is, 1.2265
0.88375
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