17) 1) If a normal distribution has a mean of 35 and a standard deviation of 10,
ID: 3324131 • Letter: 1
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17) 1) If a normal distribution has a mean of 35 and a standard deviation of 10, ther A) the median is 35 and the mode is 35. C) the median is 35 and the mode is 45. B) the median is 45 and the mode is 25. D) the median is 25 and the mode is 45. 18) Find the standard error for the given values of x and n x-125, n = 259 A) 0.483 C) 125 D) 0.517 B) 0.031 19) Find the critical value twz needed to construct a confidence interval of the given level 19) with the given sample size. Level 95%, sample size 11 A) 1.960 B) 1.812 C) 2.201 D) 2.228 20) A test is made off,: -50 versus Hi : 50. A sample of size n-71 is drawn, and x-56. The population standard deviation is -29. Compute the value of the test statistic z and determine ifHo is rejected at the = 0.05 level. A) 0.21, Ho not rejected C) 0.21, Ho rejected B) 1.74, Ho rejected D) 1.74, Ho not rejected 21) A poll found that 39% of male voters and 42% of female voters support a particular candidate. To test whether this candidate has equal levels of support between male and female voters, the alternative hypothesis should be A) H: Pmale Pfemale B) HI : Pmale 50%. c)HyPmale#39%, HI.Pfemale42%. D)Hmale Pfemale z 2 In a poll of 667 university students, 313 said that they were opposed to legalizing marijuana. Estimate the percentage of students who oppose legalizing marijuana. A) 88.4% B) 46.9% C) 11.6% D) 53.1% 23) An analysis results in a multiple regression equation of y'-68+27x, +22. We can conclude that A) This is insufficient information to assess the significance of x B) The variable x is a moderately significant factor in this model. ) The variable x is not a significant factor in this model. D) The variable xj is a very significant factor in this model.Explanation / Answer
17. A normal distribution has mean, median and mode of equal value. So option A) is correct, both median and mode are equal to 35.
18. In the absence of other info, standard error = 125/250=0.483, so option A) is correct.
19. Since sample size = 11, the critical value t0.025 can be found from a t-table with 10 degrees of freedom as 2.228. So option D) is correct.
20. Test statistic = (56-50)/(29/sqrt(71))=1.7433
Critical value corresponding to alpha = 0.05 is 1.96, as seen from a standard normal table. Since the test statistics is less than the critical value, the Null hypothesis H0 is not rejected. So option D) is correct.
21. Option A) is correct.
22. Percentage opposing legalising Marijuana = 313/667=0.4692, which is 46.9%. So option B) is correct.
23. Option A) is correct, this is insufficient information to assess the significance of x1.
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