1. The manager of a local store believes that the store\'s average daily sales a
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Question
1. The manager of a local store believes that the store's average daily sales are more than $8,000. To test her beliet, a sample of 64 days of sales was selected; and it was found that the average daily sale was $8,250 with a standard deviation (of the sample) of $1,200. Perform a hypothesis test of the manager's belief at the 5% level of significance. What is the p-value of this test and state its meaning. b. 2. From a population of cereal bexes marked "12 ounces", a sample of 16 boxes is selected and the contents of each bex is weighed. The sample revealed a mean of 11.7 ounces with a standard deviation of 0.8. Test to see if the mean of the population is at least 12 ounces. Use a 05 level of significance. 3. The business manager of a local health clinic is interested in estimating the difference betreen the fees for extended office visits in their center and the fees of a newly opened group practice. He gathered the following information regarding the two offices Health Clinic Group Practice n1-50 visits n2 45 visits -21 S1-2.75 -19 S2-3.00 Test to see if there is a significant difference between the fees charged by the two clinics. Use a 596 level. The salaries of managers at 423 convenience stores is believed to be nermally distributed. A random sample of eighteen managers is chosen. The sample average salary is S31,520 witha standard deviation of SL560. Find the 95% confidence inten al for the average alary erhnten at the 423 convenience stores. 5. A statistics professor nithes to find out the relationship between the classification of a student and the students'grade in the course. The fellowing is a breakdonn of the grades and FS F6 F7 F8 F9 F10 F11 F12 PrtscrInsert DExplanation / Answer
1.
H0: mu <= 8000
H1: mu > 8000
Test statistics, z = (8250 - 8000)/(1200/sqrt(64)) = 1.6667
p-value = 0.0478
As p-value is less than the significance level of 0.05, we reject the null hypothesis.
Evidence to conclude that daily sales is greater than 8000
2.
H0: mu <= 12
H1: mu > 12
Test statistics, t = (11.7 - 12)/(0.8/sqrt(16)) = -1.5
p-value is greater than the significance level of 0.05, we fail to reject null hypothesis.
Can not conclude that population mean is at least 12
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