Use the following table to answer the question below. Source df Sum of squares M
ID: 3321998 • Letter: U
Question
Use the following table to answer the question below.
Source
df
Sum of squares
Mean square
F value
Pr>F
Among treatments
5
70.4
14.09
2.44
0.0472
Within treatments
48
276.8
5.77
Corrected total
53
347.2
If treatment effects are considered fixed, what is the null hypothesis of the experiment?
If treatment effects are considered fixed, what is the alternative hypothesis of the experiment?
The total number of observations included in the analysis was _____.
The number of treatment groups was __________.
If each treatment received an equal number of replications, the number of replications per treatment was ___________.
What is the value of the pooled standard error of the means? ____________
If alpha is 0.01, would you reject the null hypothesis?
With the information that you have, would you recommend a mean comparison procedure?
Name an example of a mean comparison procedure?
Source
df
Sum of squares
Mean square
F value
Pr>F
Among treatments
5
70.4
14.09
2.44
0.0472
Within treatments
48
276.8
5.77
Corrected total
53
347.2
Explanation / Answer
The total number of observations included in the analysis was =df total+! =53+1=54
The number of treatment groups was =df(treatments)+1 =5+1=6
If each treatment received an equal number of replications, the number of replications per treatment was =54/6=9
value of the pooled standard error of the means =(MSE)1/2 =(5.77)1/2 =2.402
No as p vlaue is higher than 0.01 level
as we have not rejected null; mean comparison procedure is not required
Tukey HSD is one mean comparison procedure
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