MEN Sum 380609603 prices(x) 102.46 102.46 102.46 102.46 7825.1716 6004.7001 6001

Question

MEN Sum 380609603 prices(x) 102.46 102.46 102.46 102.46 7825.1716 6004.7001 6001.6009 5846.1316 5251.9009 5250.4516 52504516 4553.5504 4553.5504 4553.5504 3902.5009 2966.9809 2757.3001 2753.1009 2753.1009 2253.4009 1845.5616 1086.3616 504.4516 181 1716 167.9616 19.8916 19.8916 56.8001 8563.6516 8563.6516 9512.1009 58090.6404 60781.9716 158038.0516 24.97 24.99 77.49 77.47 380609.603 72.47 72.46 30 30 34.98 102.46 102.46 102.46 102.46 102.46 102.46 102.46 102.46 102.46 102.46 102 46 102.46 102.46 102:46 102.46 102.46 102.46 102.46 102.46 102.46 102.46 102.46 102.46 102.46 102.46 380609.603 sample Variance- -67.48 67.48 -67.48 62.47 54.47 52.51 52.47 52.47 -47.47 Sample Variance = 13124.4691 34.98 39.99 47.99 49.95 49.99 Sample Deviation v13124469 1 Sample Deviation 114562075 -4.46 98 129.97 27.51 92.54 97 53 241.02 246.54 397,54 199.99 343 48 500

Explanation / Answer

combined sample mean=(30*102.46+30*102.47)/(30+30)=102.465

standandared error of mean of combined sample=((sp*(1/n1 +1/n2)1/2) =132.25*sqrt(1/30 + 1/30)=34.15

and sp2=((n1-1)s12+(n2-1)s22)/n and with n=n1+n2-2

(1-alpha)*100% confidence interval for population mean=sample mean±t(alpha/2,n-1)*SE(sample mean)

90% confidence interval for population mean=102.465±t(0.1/2, 60-1)*34.15=102.465±1.67*34.15=102.465±57.031

=(45.434,159.496)

sample mean s2 n (n-1)s2 sample 1 102.46 13124.4691 30 380609.6039 sample 2 102.47 21855.3844 30 633806.1476 sum= 60 1014415.752 sp2= 17489.92675 sp= 132.2494868

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