which answer is correct? 1. The following statement was presented in a Tuskegee
ID: 3321974 • Letter: W
Question
which answer is correct?
1. The following statement was presented in a Tuskegee University thesis.
“Species diversity was higher (P<0.01) in wetland soils compared to upland soils.”
The (P<0.01) indicates:
a- that the probability of making a type I error is less than one in a hundred.
b- that the probability of making a type II error is less than one in a hundred.
c- that the probability of a greater F in the ANOVA table was greater than 0.01.
d- that the probability of a greater F in the ANOVA table was less than 0.01.
e- that both a and c are correct.
f- that both a and d are correct.
2. Increasing the number of replications per treatment
a) increases the standard errors of the means.
b) decreases the standard errors of the means.
c) increases the power of the experiment.
d) both a and c
e) both b and c
3. The function of replication in the one-way ANOVA is
a- to provide an estimate of experimental error.
b- to decrease precision of the standard errors
c- to offset the effects of sloppy techniques.
d- all of the above.
4. In hypothesis testing, is the probability of making a type II error. Thus, power (1-) is
a. the probability of failing to reject Ho when H1 is true.
b. the probability of failing to reject Ho when H0 is true.
c. the probability of rejecting Ho when H1 is true.
d. the probability of rejecting Ho when H0 is true.
e. the probability of failing to reject Ho.
Explanation / Answer
1. The following statement was presented in a Tuskegee University thesis. “Species diversity was higher (P<0.01) in wetland soils compared to upland soils.”
The (P<0.01) indicates:
a- that the probability of making a type I error is less than one in a hundred.
2. Increasing the number of replications per treatment
b) decreases the standard errors of the means.
c) increases the power of the experiment.
e) both b and c
4. In hypothesis testing, is the probability of making a type II error. Thus, power (1-) is
B = P(Accept H0 / H1)
1 - B = 1- P(Accept H0/H1)
c. the probability of rejecting Ho when H1 is true.
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