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With double-digit annual percentage increases in the cost of health insurance, m

ID: 3321670 • Letter: W

Question

With double-digit annual percentage increases in the cost of health insurance, more and more workers are likely to lack health insurance coverage (USA Today, January 23, 2004). The following sample data provide a comparison of workers with and without health insurance coverage for small, medium, and large companies. For the purposes of this study, small companies are companies that have fewer than 100 employees. Medium companies have 100 to 999 employees, and large companies have 1000 or more employees. Sample data are reported for 50 employees of small companies, 75 employees of medium companies, and 100 employees of large companies. Health Insurance Size of Company Yes No Total Small 36 14 50 Medium 68 7 75 Large 85 15 100 Conduct a test of independence to determine whether employee health insurance coverage is independent of the size of the company. Use = .05. Compute the value of the 2 test statistic (to 2 decimals). The p value is What is your conclusion? The USA Today article indicated employees of small companies are more likely to lack health insurance coverage. Calculate the percentages of employees without health insurance based on company size (to the nearest whole number). Small % Medium % Large % Based on the percentages calculated above, what can you conclude?

Explanation / Answer

Result:

With double-digit annual percentage increases in the cost of health insurance, more and more workers are likely to lack health insurance coverage (USA Today, January 23, 2004). The following sample data provide a comparison of workers with and without health insurance coverage for small, medium, and large companies. For the purposes of this study, small companies are companies that have fewer than 100 employees. Medium companies have 100 to 999 employees, and large companies have 1000 or more employees. Sample data are reported for 50 employees of small companies, 75 employees of medium companies, and 100 employees of large companies.

Health Insurance Size of Company Yes No Total

Small 36 14 50

Medium 68 7 75

Large 85 15 100

Conduct a test of independence to determine whether employee health insurance coverage is independent of the size of the company. Use = .05.

Compute the value of the 2 test statistic 7.91 (to 2 decimals).

The p value is 0.0191

What is your conclusion?

O is rejected.

The employee health insurance coverage is not independent of the size of the company.

The USA Today article indicated employees of small companies are more likely to lack health insurance coverage.

Calculate the percentages of employees without health insurance based on company size (to the nearest whole number).

Small 28% Medium 9% Large 15% Based on the percentages calculated above, what can you conclude?

The data support the article that employees of small companies are more likely to lack health insurance coverage.

Chi-Square Test

Observed Frequencies

Column variable

Calculations

Row variable

yes

no

Total

fo-fe

small

36

14

50

-6

6

medium

68

7

75

5

-5

large

85

15

100

1

-1

Total

189

36

225

Expected Frequencies

Column variable

Row variable

yes

no

Total

(fo-fe)^2/fe

small

42

8

50

0.8571

4.5000

medium

63

12

75

0.3968

2.0833

large

84

16

100

0.0119

0.0625

Total

189

36

225

Data

Level of Significance

0.05

Number of Rows

3

Number of Columns

2

Degrees of Freedom

2

Results

Critical Value

5.9915

Chi-Square Test Statistic

7.9117

p-Value

0.0191

Reject the null hypothesis

Chi-Square Test

Observed Frequencies

Column variable

Calculations

Row variable

yes

no

Total

fo-fe

small

36

14

50

-6

6

medium

68

7

75

5

-5

large

85

15

100

1

-1

Total

189

36

225

Expected Frequencies

Column variable

Row variable

yes

no

Total

(fo-fe)^2/fe

small

42

8

50

0.8571

4.5000

medium

63

12

75

0.3968

2.0833

large

84

16

100

0.0119

0.0625

Total

189

36

225

Data

Level of Significance

0.05

Number of Rows

3

Number of Columns

2

Degrees of Freedom

2

Results

Critical Value

5.9915

Chi-Square Test Statistic

7.9117

p-Value

0.0191

Reject the null hypothesis

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