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Have Excel pick a random number between 0 and 9 (you can do this with the functi

ID: 3321410 • Letter: H

Question

Have Excel pick a random number between 0 and 9 (you can do this with the function =Randbetween (0, 9) ), using 2000 pairs of random numbers. Then ask Excel to run the linear regression between these two columns and generate a p-value for testing the significance of the linear relationship between X and Y. Use a significance level (alpha) of 10%. Have Excel calculate the slope, intercept, correlation, p-value.

My results found:

Trial #

Slope

Intercept

Correlation

P-Value of Slope

Significant?

1

-0.01

4.50

0.01

0.56

No

***QUESTION TO BE ANSWERED:

Calculate the 95% prediction interval of y when x=5 using the 2000 pairs.

Trial #

Slope

Intercept

Correlation

P-Value of Slope

Significant?

1

-0.01

4.50

0.01

0.56

No

Explanation / Answer

As all required data not available the calculation is redine using 2000 random data pairs in excel.

Result of the same is given below :

95% prediction Interval   

a + bx0 +/- t0.025 * se * Sqrt(1/n +(x0-xbar)2/Sxx)

Parameters are

a

b

t0.025

Se

n

xo

xbar

Sxx

4.3607

0.005

1.96

2.889928

2000

5

4.513

16097.66

Hence Confidence Interval is

4.3857

+/-

0.128509

Calculation for Sxx

xbar

4.513

Sum xi sqr

56832

sum xi

9026

Sqr(sumxi)

81468676

Sqr(sumxi)/n

40734.34

Sxx = Sum xi sqr - Sqr(sumxi)/n

16097.66

SUMMARY OUTPUT Regression Statistics Multiple R 0.005065 R Square 2.57E-05 Adjusted R Square -0.00047 Standard Error 2.889928 Observations 2000 C ANOVA df SS MS F Significance F Regression 1 0.428115 0.428115 0.051261 0.820907 Residual 1998 16686.66 8.351682 Total 1999 16687.09 Coefficients Standard Error t Stat P-value Lower 95% Upper 95% Lower 90.0% Upper 90.0% Intercept 4.360726 0.121419 35.91466 2.3E-218 4.122605 4.598848 4.160917 4.560536 X Variable 1 0.005157 0.022777 0.226409 0.820907 -0.03951 0.049827 -0.03233 0.04264
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