Next Question 8 of 16 (1 point) View problem in a pop-up 4.1 Section Exercise 2

Question

Next Question 8 of 16 (1 point) View problem in a pop-up 4.1 Section Exercise 2 below. 043% A 40% B 11% AB 6% Source: www.infoplease.com Download data Choose one American at random. Find the probabilities of the following. Part 1 Has type O blood The probability that a random American has type O blood is 0.43 ). Part 2 Has type B or AB The probability that a random American has type B or AB is 0.17 -- Part 3 out of 3 Does not have type A or AB The probability that a random American does not have type A or AB is 7 Show More

Explanation / Answer

The probability that random anerican has type B or AB is

P(B or AB) = P(B) + P(AB) = 0.11 + 0.06 = 0.17

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The probability that random american has not type A or AB is

P(not type A or AB) = P(not A and not AB) = P(O or B) = P(O) + P(B) = 0.43+0.11= 0.54

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