8. A service station has both self-service and full-service islands. On each isl
ID: 3320761 • Letter: 8
Question
8. A service station has both self-service and full-service islands. On each island there is a single regular unleaded pump with two hoses. Let X denote the number of hoses used on the self-service island at a particular time, and let Y denote the num on t ber of hoses he full-service island in use at that time. The joint probability mass function of X and Y is given below. Px) o 1 2 0 0.10 0.04 0.02 x 0.08 0.20 0.06 2 0.06 0.14 0.30 (a) Find P(XSI, Y-2) Answer o O% (b) Find the marginal distribution of X. pta lo16 lo-y lo.so (c) Find the expected value of Y. AnswerIuExplanation / Answer
a) The required probability here is computed as:
P(X <= 1, Y = 2) = P(X = 0, Y = 2) + P(X =1, Y = 2) = 0.02 + 0.06 = 0.08
Therefore 0.08 is the required probability here.
b) The marginal PDF for X here is obtained by adding the corresponding rows as:
P(X = 0) = 0.16,
P(X = 1) = 0.34,
P(X = 2) = 0.50
c) The expected value of Y here is obtained as:
E(Y) = 0 + 1*0.38 + 2*0.38 = 1.14
Therefore 1.14 is the expected value of Y here.
d) The second moment of Y here is obtained as:
E(Y2) = 0 + 12*0.38 + 22*0.38 = 1.9
Now the variance is computed as:
Var(Y) = E(Y2) - [ E(Y)]2 = 1.9 - 1.142 = 0.6004
Therefore 0.6004 is the required variance here.
e) The expected value of XY here is computed as:
E(XY) = 1*0.2 + 2*(0.06 + 0.14) + 4*0.3 = 1.8
Therefore 1.8 is the expected value here.
f) P(X = 0) = 0.16, P(Y = 0) = 0.24
P(X = 0)P(Y = 0) = 0.16*0.24 = 0.0384
P(X = 0, Y = 0) = 0.10 which is not equal to P(X = 0)P(Y = 0)
Therefore X and Y are not independent here.
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