In a study, hemodynamic stresses were measured on subjects undergoing laparoscop
ID: 3319986 • Letter: I
Question
In a study, hemodynamic stresses were measured on subjects undergoing laparoscopic cholecystectomy. An outcome variable of interest was the ventricular end diastolic volume (LVEDV) measured in milliliters. A portion of the data appear in the following table. Baseline refers to a measurement taken 5 minutes after induction of anesthesia, and the term “5 minutes” refers to a measurement taken 5 minutes after baseline.
LVEDV mL
Subject Baseline 5 Minutes
1 51.7 49.3
2 79.0 72.0
3 78.7 87.3
4 80.3 88.3
5 72.0 103.3
6 85.0 94.0
7 69.7 94.7
8 71.3 46.3
9 55.7 71.7
10 56.3 72.3
By HAND use the appropriate nonparametric test to answer the following question:
Can we conclude, on the basis of these data, that among subjects undergoing laparoscopic cholecystectomy, he average LVEDV levels change? Let = 0.01.
Explanation / Answer
Non parametric test is such as chisquare test
Given that,
population variance (^2) =453.451
sample size (n) = 10
sample variance (s^2)=135.624
null, Ho: ^2 =453.451
alternate, H1 : ^2 !=453.451
level of significance, = 0.01
from standard normal table, two tailed ^2 /2 =21.666
since our test is two-tailed
reject Ho, if ^2 o < - OR if ^2 o > 21.666
we use test statistic chisquare ^2 =(n-1)*s^2/o^2
^2 cal=(10 - 1 ) * 135.624 / 453.451 = 9*135.624/453.451 = 2.692
| ^2 cal | =2.692
critical value
the value of |^2 | at los 0.01 with d.f (n-1)=9 is 21.666
we got | ^2| =2.692 & | ^2 | =21.666
make decision
hence value of | ^2 cal | < | ^2 | and here we do not reject Ho
^2 p_value =0.9753
ANSWERS
---------------
null, Ho: ^2 =453.451
alternate, H1 : ^2 !=453.451
test statistic: 2.692
critical value: -21.666 , 21.666
p-value:0.9753
decision: do not reject Ho
we do not have enough evidence to support the claim that among subjects undergoing laparoscopic cholecystectomy, he average LVEDV levels change
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