Using the attached data, we like to test that mean price of neutral is lower tha

Question

Using the attached data, we like to test that mean price of neutral is lower than mean price of sad with 0.05 significance. Do manually a test using the assumption. neutral sad 1.00 2.50 3.00 4.00 1.00 1.50 4.00 1.00 1.50 3.50 . 0.50 0.50 3.00 1.50 2.00 0.00 3.50 2.50 0.00 1.00 2.00 0.00 0.00 0.00 1.00 2.00 0.00 0.00 (note: you need to set up, compute statistics, cv from a table, conclusion, implication and error statements for each test.) 1) we assume that variance of neutral = 0.6 and variance of sad = 1.3 2) We assume that variances are unknown but same 3) We assume that variances are unknown and not same 4) do #2 and #3 again using ttest in R studio. Just write down conclusion using p-value (note: in ttest, you need to put "mu = 0") 5) do shapiro test to see that data are from normal 6) write down implication of shapiro test for validity of t test 1.00 0.00 0.50

Explanation / Answer

Using Minita:

Stat --> 2 sample t tests

Two-Sample T-Test and CI: neutral, sad

Two-sample T for neutral vs sad

N Mean StDev SE Mean
neutral 14 0.536 0.746 0.20
sad 17 2.12 1.24 0.30

Difference = (neutral) - (sad)
Estimate for difference: -1.582
95% upper bound for difference: -0.965
T-Test of difference = 0 (vs <): T-Value = -4.37 P-Value = 0.000 DF = 26

P-value <0.05 we reject the nullhypothesis. we conclude that mean proce of neutral is not less than mean price of sad.

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