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11.8 7.7 9.0 7.4 7.3 7.0 6.8 7,8 6.3 9.7 8.17.7 9.7 10.7 8.0 8.7 7.9 11.3 7.2 6.

ID: 3318740 • Letter: 1

Question

11.8 7.7 9.0 7.4 7.3 7.0 6.8 7,8 6.3 9.7 8.17.7 9.7 10.7 8.0 8.7 7.9 11.3 7.2 6.3 6.8 5,7 6.5 8.8 11.6 7.0 7.3 Calculatepoint estimate of the mean value of strength for the conceptual population of all beams manufactured in this fashion. [Hint: Di-220.1.] (Round your answer to three decimal place 8.152 MPa State which estimator you used (b) Calculate a point estimate of the strength value that separates the weakest 50% of all such beams from the strongest 5096. 7.7 MPa State which estimator you used (c) Calculate a point estimate of the population standard deviation . [Hint: Dy2 . 1867.51.] (Round your answer to three decimal places.) 1.647 x MPa Interpret this point estimate This estimate describes the bias of the data. This estimate describes the center of the data o This estimate describes the spread of the data This estimate describes the linearity of the data. Which estimator did you use? (d) Calculate a point estimate of the proportion of all such beams whose flexural strength exceeds 10 MPa. [Hint: Think of an observation as a "success" if it exceeds 10.] (Round your answer to three decimal places.) (e) Celculate a point estimate of the population coefficient of variation ol. (Round your answer to four decimal places.) State which estimator you used

Explanation / Answer

Solution:- Given that 11.8,7.7,9.0,7.4,7.3,7.0,6.8,7.8,6.3,9.7,8.1,7.7,9.7,10.7,8.0,8.7,7.9,11.3,7.2,6.3,6.8,5.7,6.5,8.8,11.6,7.0,7.3

c) standard deviation:- 1.679

  s = sqrt(s^2) = sqrt((1867.51 - ((220.1)^2/27))/26 ) = 1.6789

d) 4/27 =0.148

e) 1.679/8.152 = 0.2060