In the game of roulette, a player can place a $5 bet on the number 27 and have a

ID: 3317871 • Letter: I

Question

In the game of roulette, a player can place a

bet on the number

and have a

1/38

probability of winning. If the metal ball lands on

27,

the player gets to keep the

paid to play the game and the player is awarded an additional

$175.

Otherwise, the player is awarded nothing and the casino takes the player's

What is the expected value of the game to the player? If you played the game 1000 times, how much would you expect to lose?

The expected value is

$nothing .

(Round to the nearest cent as needed.)

The player would expect to lose about

$nothing .

(Round to the nearest cent as needed.)

The expected value is sum of (outcome x probability)

= 175x1/38 + -5x37/38

= -10/38

= $-0.26

If the game is played 1000 times, the player would expect to lose about 1000x10/38 = $263.16

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