Aquatic fungi called hyphomycetes play important roles in decomposing plant mate
ID: 3317857 • Letter: A
Question
Aquatic fungi called hyphomycetes play important roles in decomposing plant material such as leaves in streams and lakes. In many environments, these fungi are the most important decomposers. Some researchers were interested to see how urban pollution influenced the decomposition rate of these fungi so they selected two relatively polluted sites L1 and L6 on a river in Portugal and an unpolluted site (L7) on the same river. At each site they submerged 6 bags of leaf litter and allowed them to decompose for a month. They then estimated the amount of fungi present by measuring the amount of ergosterol (the sterol in the cell membranes of fungi instead of cholesterol) and used a conversion factor to convert that into mg of fungal biomass per g of the leaf sample. From these data they calculated a decomposition rate for each bag at each site. Then they compared the average decomposition rates at these sites.
What would be the null hypothesis? The alternative hypothesis?
A. = 0
B. 1 - 2 > 0
C. p1 > p0
D. The observed data are consistent with our expectations under the null (hypothetical) distribution.
E. 0
F. µ1 - µ2 0
G. The observed data are not consistent with our expectations under the null (hypothetical) distribution.
H. µ1 - µ2 > 0
I. The distribution of these data are consistent with a normal distribution.
J. 1 - 2 = 0
K. 0
L. 1 - 2 < 0
M. p1 = p0
N. µ1 - µ2 < 0
O. 1 - 2 0
P. The group variances within these data are approximately equal.
Q. p1 p0
R. The group variances within these data are not approximately equal.
S. µ1 - µ2 0
T. The means (µ) of the decomposition rates are all equal (i.e. µ1 = µ2 = µ3...).
U. Pr[1 and 2] Pr[1] * Pr[2]
V. µ1 - µ2 0
W. p1 p0
X. = 0
Y. 1 - 2 0
Z. p1 p0
AA. The distribution of these data are not consistent with a normal distribution.
BB. 1 - 2 0
CC. Pr[1 and 2] = Pr[1] * Pr[2]
DD. µ1 - µ2 = 0
EE. p1 < p0
Explanation / Answer
null hypotheiss H0: T. The means (µ) of the decomposition rates are all equal (i.e. µ1 = µ2 = µ3...).
alternate hypothesis H1: atleast one mean differ from another
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