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A 63% 42 Wed 4:37 PM Q = É Safari File Edit View History Bookmarks Window Help .

ID: 3317527 • Letter: A

Question

A 63% 42 Wed 4:37 PM Q = É Safari File Edit View History Bookmarks Window Help ... DO Please Help Me Thanks! | Chegg.com A newconnect.mheducation.com Connect Chapter 10 0 Saved Help Save & Exit Submit reen Shot 12.17.41 PM Check my work reen Shot 12...17.44 PM Watch Corporation of Switzerland claims that its watches on average will neither gain nor lose time during a week. A sample of 18 watches provided the following gains (+) or losses (-) in seconds per week. A Click here for the Excel Data File points -0.38 -0.20 -0. 38-0.32+0.32 -0.23+0.30 +0.25 -0.10 -0.37 -0.61 -0.48 -0.47 -0.64 -0.04-0.20 -0.68 #0.05 eBook reen Shot 12...20.32 PM Print References a-1. Is it reasonable to conclude that the mean gain or loss in time for the watches is 0? Use the .05 significance level. (Negative amounts should be indicated by a minus sign. Round your answers to 3 decimal places.) reen Shot 12...0.38 PM At a level of .05 significance, we reject HO: p= Oift · reen Shot 12...22.25 PM a-2. Compute the value of the test statistic. (Negative amount should be indicated by a minus sign. Round your answer to 3 decimal places.) Value of the test statistic reen Shot 12...22.27 PM MC reen Shot 12.4,44 PM 9OOIDO IDIO @ BOO A OTN IEEE

Explanation / Answer

The statistical software output for this problem is:

One sample T hypothesis test:
: Mean of variable
H0 : = 0
HA : 0

Hypothesis test results:

Hence,

a - 1) Degrees of freedom = n - 1 = 18 - 1 = 17

Hence,

Reject Ho if t < - 2.110 or t > 2.110

a - 2) Test statistic = - 3.158

a - 3) Reject; p - Value = 0.0057

Variable Sample Mean Std. Err. DF T-Stat P-value Data -0.23222222 0.073536064 17 -3.1579365 0.0057
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