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2. 120 points) A mail-order computer business has five telephone lines. Let X de

ID: 3317098 • Letter: 2

Question

2. 120 points) A mail-order computer business has five telephone lines. Let X denote the number of lines in use at a specified time. Suppose the pmf of X is as given in the accompanying table. 0.18 0.15 0.20 0.22 0.25 Calculate the probability of each of the following events. a. at least 3 lines are in use b. between 2 and 4 lines, inclusive, are not in use 120 points] Consider a class of 20 students. Answer the following questions. 3. Findings of a research states that the probability of an individual who is left-handed is 0.20 What is the probability that the number of left-handers in the class is less than 4? a. b. If you select two students randomly, what is the probability that both of them are left-handers?

Explanation / Answer

QUestion 3

(A) Pr(at least 3 lines are in use) = Pr( X = 3) + Pr( X = 4)

= 0.22 + 0.25

= 0.47

(B) Here it is asked that from 2 to 4 are not in use that means we can use 0 and 1 number of telephone lines

Pr(X = 0 & X = 1) = Pr( X = 0 ) + Pr(X =1)

= 0.18 + 0.15 = 0.33

Question 4

Number of studnets in class n = 20

Pr(left handed) = 0.20

The given distibution is binomial distribution

(a) Pr(NUmber of left handers are less than 4) = Pr(X < 4) = BINOMIAL (X < 4 ; 20 ; 0.2)

By checking binomial table

Pr(X <4) = 0.4114

(b) If two students chosing randomly than the probability that both will be left handed = Pr(First student is left - handed ) * Pr(second student is also left handed) = 0.2 * 0.2 = 0.04