22-2 5 s2 2 2 522 s 222 2 2 2 2 2 2 2 5 2 3S225 222222222235 552?3 22 2222?3Z2S

Question

22-2 5 s2 2 2 522 s 222 2 2 2 2 2 2 2 5 2 3S225 222222222235 552?3 22 2222?3Z2S 223 ,2 17 19 2 S 28 2 1 9 1 3 4.87, 18-16 16 21 10 5 8.4 20-9 12, 26 9 4 11 9: 16-16 10 4!7 9 16 16 19 20 24 21 8-16 15 14 20 23 272 15 7 9 24 13 21 Po 200 200 200 two 200 200 200 200 200 200 two 200 200 200 200 200 200 200 zin zio zio zio ise 06. 2 223 2 225 32 4 4.6. 3 s 334 3:5333 6 5 336.6 4,347 65 Go 200 200 200 200 210 210 200 210 200 200 200 250 210 200 200 200 200 200 two 200 990 210 200 220 200 200 200 200 une 200 200 200 200 43 2.2 26 2.3.4.426 4 2 3 4 5.3- 24 25 26 27 29 30 31 32 33 34 35 36 37 30, 39 40 41 42 43 44 45 46 47 48 49 50 srezas ,, 1234.567 8. 9-10-11 12 13 14 15 16 17 18 19 20 21 22

Explanation / Answer

(1)

X=no.of badrooms

Mean=sum X*P(X=x)

=(2*24+3*26+4*26+5*11+6*14+7*2+8*2)/105

=399/105=3.8

variance=E(X^2)-(E(X))^2

E(X^2)=(4*24+9*26+16*26+25*11+36*14+49*2+64*2)/105

=115,460/105=1099.6190

V(X)=1099.6190-3.8^2

=1085.1790

(2)

X=no. of bathroom

using above formula

mean=(1.5*16+2*65+2.5*17+3*7)/105

=217.5/105=2.0714

E(X2)=(2.25*16+4*65+6.25*17+9*7)/105

=469.25/105=4.4690

v(X)=4.4690-2.0714^2=0.178349

X= 2 3 4 5 6 7 8 total no. of X 24 26 26 11 14 2 2 105 P(X=x) 24/105 26/105 26/105 11/105 14/105 2/05 2/105 1

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