A university would like to estimate the proportion of fans who purchase concessi

Question

A university would like to estimate the proportion of fans who purchase concessions at the first basketball game of the season. The basketball facility has a capacity of
3,600and is routinely sold out. It was discovered that a total of 220 fans out of a random sample of 500 purchased concessions during the game. Construct a 95% confidence interval to estimate the proportion of fans who purchased concessions during the game.The 95% confidence interval to estimate the proportion of fans who purchased concessions during the game is
left parenthesis nothing comma nothing right parenthesis,.

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(Round to three decimal places as needed.)

Explanation / Answer

p is 220/500=0.44 and N is 500

z for 95% confidence is 1.96

the lower bound is p-z*sqrt(p*(1-p)/N) =0.44-1.96*sqrt(0.44*(1-0.44)/500)=0.396

upper bound is p+z*sqrt(p*(1-p)/N) =0.44+1.96*sqrt(0.44*(1-0.44)/500)=0.484

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