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You are conducting a multinomial Goodness of Fit hypothesis test for the claim t

ID: 3316397 • Letter: Y

Question

You are conducting a multinomial Goodness of Fit hypothesis test for the claim that the 4 categories occur with the following frequencies:

HoHo : pA=0.2;  pB=0.2; pC=0.3; pD=0.3



Complete the table. Report all answers accurate to three decimal places.



What is the chi-square test-statistic for this data?
2=2=

What is the P-Value?
P-Value =  


For significance level alpha 0.1,

What would be the conclusion of this hypothesis test?

Reject the Null Hypothesis

Fail to reject the Null Hypothesis

Category Observed
Frequency Expected
Frequency A 17 B 33 C 32 D 39

Explanation / Answer

observed frequncies are Oi

17 33 32 39   

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expected frequencies are Ei

0.2*sum(17+33+32+39) = 24.2

0.2*sum(17+33+32+39) = 24.2

0.3*sum(17+33+32+39) = 36.3

0.3*sum(17+33+32+39) = 36.3

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and claiming hypothesis is

null, Ho: proportion are equal acorss

alternative, H1: atleast one proportion is different among them

level of significance, = 0.1

from standard normal table, chi square value at right tailed, ^2 /2 =4.6052

since our test is right tailed,reject Ho when ^2 o > 4.6052

we use test statistic ^2 o = (Oi-Ei)^2/Ei

from the table take sum of (Oi-Ei)^2/Ei, we get ^2 o = 6.0523

critical value

the value of |^2 | at los 0.1 with d.f, n - 1 = 3 - 1 = 2 is 4.6052

we got | ^2| =6.0523 & | ^2 | =4.6052

make decision

hence value of | ^2 o | > | ^2 | and here we reject Ho

^2 p_value =0.0485

ANSWERS

---------------

null, Ho: proportion are equal acorss

alternative, H1: atleast one proportion is different among them

test statistic: 6.0523

critical value: 4.6052

p-value:0.0485

decision: reject Ho

Observed (Oi ) Expected ( Ei) Oi-Ei (Oi-Ei)^2 (Oi-Ei)^2/Ei 17 24.2 -7.2 51.84 2.1421 33 24.2 8.8 77.44 3.2 32 36.3 -4.3 18.49 0.5094 39 36.3 2.7 7.29 0.2008
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