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Previous 1 2 3 4 5 6 7 89 10 Next Question 10 of 12 (1 point) View problem in a pop-up 4.2 Section Exercise 19 The frequency distribution shown here illustrates the number of medical tests conducted on 39 randomly selected emergency patients. Number of tests performed Number of patients 4 or more 10 Download data If a patient is selected at random, find the probability for the following. Enter your answers as fractions or as decimals rounded to 3 decimal places. Part 1 out of 3 P( patient has had exactly 3 tests done) - Subr

Explanation / Answer

Total number of patients = 11+9+3+6+10 = 39

Probability that a randomly selected patient has had exactly 3 tests done = Number of patients with '3' number test performed / Total number of patients = 6/39.

P(patient has had exactly 3 tests done ) = 6/39 = 2/13 = 0.154

X : Number of Test performed

The below table provides probabilities for X=0,1,2,3 and 4 or more

Probability that a patient had 'X' of test performed = Number of patients with 'X' number test performed / Total number of patients

X:Number of Tests performed Number of patients Probability that X: number of tests performed 0 11 11/39 1 9 9/39 2 3 3/39 3 6 6/39 4 or more 10 10/39 Total 39

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