27. Resting pulse rates for a random sample of 26 smokers had a mean deviation o

Question

27. Resting pulse rates for a random sample of 26 smokers had a mean deviation of 5 bpm. Among 32 randomly chosen Both sets of data were roughly symmetric. Is there evidence of a non-smokers at the a-.05 Run a con group 2 be the non-smokers.(15 pts) of 80 beats per minute (opm) and a standard non-smokers, the mean and standard deviation were 74 and 6 bpm difference in mean pulse rate between smokers and us level of significance? Run a confidence interval if there is. Let group 1 be the smokers and Null Hypothesis: Alternative Hypothesis what test did you run_ Indicate what you put into the calculator: p-value: Decision (reject/fail to reject Ho) Thereenough evidence to conclude that there is a difference in mean resting pulse rate between smokers and non-smokers. Confidence Interval between- and confident that the true difference in resting pulse rate is Interpretation: we are, bpm slower in non-smokers. B. Suppose we made an incorrect decision. What type of error was made? Type 1 Error B. Type Il error a.

Explanation / Answer

(a)

Null hypothesis: There is no satistically significant difference in mean of smoker and non- smoker group.

Alternative hypothesis: There is no satistically significant difference in mean of smoker and non- smoker group.

Here, We test the two sample T test for independent sample.

we put mean and sd of both sample also sample size % of LOS.

sample size1=26 sample size2=32

mean1=80 mean2=74

sd1=5 sd2=6

t=(mean1-mean2)/sqrt(SE*(1/N1+1/N2))

where SE=(N1-1)S1^2+(N2-1)S2^2/N1+N2-2

t=4.0756

df=56

pvalue=0.000146

pvalue<0.05

reject the null hypothesis

There is enough evidence to concludethat there difference in mean of smoker and non- smoker group.

confidence interval=(3.05,8.95)

95% 3.05 8.95

(b)type-I error that accept the false hypothesis.

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