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Read, Study & Practice Assignment Gradebook ment> Open Assignment FULL SCREEN PR

ID: 3315903 • Letter: R

Question

Read, Study & Practice Assignment Gradebook ment> Open Assignment FULL SCREEN PRINTER VERSION 4 BAC NMENT The following information was obtained from two independent samples selected from two normally distributed populations with unknown but equal standard deviations. ter 10.2 apter 10 Section 22. Go Tutorial 13 14 9 12 8 10 5 10 9 12 16 Sample 1 Sample 2 16 18 11 19 14 17 13 16 17 18 22 12 sem l a. Let 1 be the mean of population 1 and 2 be the mean of population 2, what is the point estimate 1-Hz ? hapter 10, Sectio - Roundyouranswer to two decimal places. The port estimate 1-2 151-535 b. Determine the 80% confidence interval for - Round your answers to two decimal places The La view Results by 80% confidence interval for 1-p2 is from to

Explanation / Answer

x1bar - x2bar -5.36 Confidence Interval (x1bar - x2bar) +/- ME SE 1.2967 Lower bound -7.07178 CI 80% Upper bound -3.64034 DF 21 Confidence Interval (-7.0718 , -3.6403 ) t-value 1.3232 ME = t*SE 1.7157 x1(bar) 10.73 x2(bar) 16.08 s1 3.07 s2 3.15 n1 11 n2 12 SE = sqrt[ (s12/n1) + (s22/n2) ] (s12/n1) 0.8562 (s22/n2) 0.8251 SE 1.2967 DF = (s12/n1 + s22/n2)2 / { [ (s12 / n1)2 / (n1 - 1) ] + [ (s22 / n2)2 / (n2 - 1) ] } [ (s12 / n1)2 / (n1 - 1) ] 0.073 [ (s22 / n2)2 / (n2 - 1) ] 0.06 (s12/n1 + s22/n2)2 2.83 DF = 21