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Safari File Edit View History Bookmarks Window Help O 4)) 100%,00 Mon 5:22 PM Allis Adimey Q E ED webassign.net 0 Mail - allisadimey Knights.ucf.edu Final Exam Chegg Study | Guided Solutions a If one sample has n = 6 and SS 4. 36. -10 points DevoreStat9 8.E.026 My Notes Ask Your Teacher The recommended daily dietary allowance for zinc among males older than age 50 years is 15 mg/day. An article reports the following summary data on intake for a sample of males age 65-74 years: n 115, x 12.4, and s 6.73. Does this data indicate that average daily zinc intake in the population of all males age 65-74 falls below the recommended allowance? (Use 0.05.) State the appropriate null and alternative hypotheses. Ho: -15 Ha: 15 Ho: -15 Hai 15 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) p-value = State the conclusion in the problem context. Reject the null hypothesis. There is not sufficient evidence that average daily zinc intake falls below 15 mg/day. Do not reject the null hypothesis. There is not sufficient evidence that average daily zinc intake falls below 15 mg/day. Reject the null hypothesis. There is sufficient evidence that average daily zinc intake falls below 15 mg/day. Do not reject the null hypothesis. There is sufficient evidence that average daily zinc intake falls below 15 mg/day. You may need to use the appropriate table in the Appendix of Tables to answer this question 4

Explanation / Answer

The statistical software output for this problem is:

One sample Z summary hypothesis test:
: Mean of population
H0 : = 15
HA : < 15
Standard deviation = 6.73

Hypothesis test results:

Hence,

Hypotheses: Option A is correct.

z = -4.14

p - Value = 0.0000

Conclusion: Option C is correct.

Mean n Sample Mean Std. Err. Z-Stat P-value 115 12.4 0.62757574 -4.1429263 <0.0001

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