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The owner of Maumee Ford Mercury Volvo wants to study the relationship between t

ID: 3315047 • Letter: T

Question

The owner of Maumee Ford Mercury Volvo wants to study the relationship between the age of a car and it's selling price.

of Maumee Ford Mercury-Volvo wants to study the relationship between the age of a car and its selling price. Listed below is a random sample of 12 used cars sold at the dealership during the last year Car Age (years) Seling Price (5000) Car Age (years) Selling Price (5000) 2 3 4. 5 6 8 16 18 9 8 12.2 11.0 4.9 4.1 6.7 13.6 10 16 14 18 6 6 11.1 9.0 9.0 4.2 12.1 10.4 8 9 10 12 Click here for the Excel Data File (a) Determine the regression equation. (Round your answers to 3 decimal places. Negative values should be indicated by a minus sign.) a F (b) Estimate the selling price of a 7-year-old car (in S000) (Round your answer to 3 decimal places.) Selling price (c) Interpret the regression equation (in dollars). (Round your answer to nearest dollar amount.) For each additional year, the car decreases S in value

Explanation / Answer

SUMMARY OUTPUT

Regression Statistics

Multiple R

0.78

R Square

0.61

Adjusted R Square

0.57

Standard Error

2.17

Observations

12

ANOVA

df

SS

MS

F

Significance F

Regression

1

73.38

73.38

15.57

0.00

Residual

10

47.14

4.71

Total

11

120.52

Coefficients

Standard Error

t Stat

P-value

Lower 95%

Upper 95%

Intercept

15.69

1.80

8.71

0.00

11.68

19.71

Age (x)

-0.57

0.14

-3.95

0.00

-0.89

-0.25

Car

Age (x)

Selling Price (y)

x^2

y^2

xy

1

11

12.2

121

148.84

134.2

2

8

11

64

121

88

3

16

4.9

256

24.01

78.4

4

18

4.1

324

16.81

73.8

5

9

6.7

81

44.89

60.3

6

8

13.6

64

184.96

108.8

7

10

11.1

100

123.21

111

8

16

9

256

81

144

9

14

9

196

81

126

10

18

4.2

324

17.64

75.6

11

6

12.1

36

146.41

72.6

12

6

10.4

36

108.16

62.4

140

108.3

1858

1097.93

1135.1

a)

b1= nE(xy)-ExEy/nE(x2)-(Ex2)

=12*1135.1-(140*108.3)/12*1858-(140*140)

=-0.5715

b0=Ey-b1Ex/n

=108.3-(-0.5715*140)/12

=188.31/12

=15.6925

b)

y=15.6925-0.5715x

y=15.6925-0.5715*7

y=15.6925-4.0005

y=11.692

c)

$571.5 (0.5715*1000)

SUMMARY OUTPUT

Regression Statistics

Multiple R

0.78

R Square

0.61

Adjusted R Square

0.57

Standard Error

2.17

Observations

12

ANOVA

df

SS

MS

F

Significance F

Regression

1

73.38

73.38

15.57

0.00

Residual

10

47.14

4.71

Total

11

120.52

Coefficients

Standard Error

t Stat

P-value

Lower 95%

Upper 95%

Intercept

15.69

1.80

8.71

0.00

11.68

19.71

Age (x)

-0.57

0.14

-3.95

0.00

-0.89

-0.25

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