The C. F. Eye Care company manufactures lenses for transplantation into the eye
ID: 3314735 • Letter: T
Question
The C. F. Eye Care company manufactures lenses for transplantation into the eye following cataract surgery. An engineering group has conducted an experiment involving two factors to determine their effect on the lens polishing process. The results of this experiment are summarized in the following ANOVA display:
Answer the following questions about the experiment:
1 Determine the values of Xi such that i = 1,2,3,4?
2 How many levels of factor A used in the experiment?
3 How many levels of factor B the group used in the experiment?
4 How many replicates the group used in the experiment?
5 Give an estimate of the standard deviation of the response variable?
6 would you conclude that the effect of factor B depends on the level of factor A? consider alpha = 0.05.
Source DF SS MS F P-value Factor A X1 X2 0.0833 0.05 0.952 Factor B X3 96.333 96.333 57.80 <0.001 Interaction 2 12.167 6.0833 3.65 - Error 6 10 X4 Total 11 118.667Explanation / Answer
Source
DF
SS
MS
F
P-value
Factor A
X1
X2
0.0833
0.05
0.952
Factor B
X3
96.333
96.333
57.80
<0.001
Interaction
2
12.167
6.0833
3.65
-
Error
6
10
X4
Total
11
118.667
1 Determine the values of Xi such that i = 1,2,3,4?
X2= tss- all sumof squears =118.667-10-12.167-96.333=0.167
X1: df = ss/ mss= 0.167/0.0833=2
X3: df = 11-6-2-2= 1
X4= ss/df=10/6=1.67
Source
DF
SS
MS
F
P-value
Factor A
2
0.167
0.0833
0.05
0.952
Factor B
1
96.333
96.333
57.80
<0.001
Interaction
2
12.167
6.0833
3.65
-
Error
6
10
1.67
Total
11
118.667
2 How many levels of factor A used in the experiment?
Level = df+1= 2+1 = 3
3 How many levels of factor B the group used in the experiment?
Level = df+1= 1+1 =2
4 How many replicates the group used in the experiment?
Number of rows is replicates= 2
5 Give an estimate of the standard deviation of the response variable?
Standard deviation of response = sqrt(MSE)=1.29
6 would you conclude that the effect of factor B depends on the level of factor A? consider alpha = 0.05.
Interaction p-values is o.04
So there is no intraction between the level A and level B,
there is no effect of factor B depends on the level of factor A
Source
DF
SS
MS
F
P-value
Factor A
X1
X2
0.0833
0.05
0.952
Factor B
X3
96.333
96.333
57.80
<0.001
Interaction
2
12.167
6.0833
3.65
-
Error
6
10
X4
Total
11
118.667
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