Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

1. Out of state tuition (in dollars) for random samples o both public and privat

ID: 3314413 • Letter: 1

Question

1. Out of state tuition (in dollars) for random samples o both public and private four-years colleges in a New England state are listed below. Do the data present enough evidence that mean out of state tuition for private colleges ( .) is higher than mean out of state tuition for public colleges ( .)? Test using 5% significance level. Assume normal populations with different standard deviations. Use p-value method Public Private 13600 13495 23400 16590 17300 12500 7050 9000 7050 16100 6450 9758 7871 2. Commuting in Calgary. Each person in two independent large random samples of male and female working adults in Calgary, Canada, was asked how long, in minutes, his or her typical daily commute was. The 99% confidence interval for the difference between true mean commute times for male and female working Calgary residents , ( -- is (-3.97 minutes, 6.37 minutes) This interval presents no convincing evidence at -ool that mean commute times for male and female working Calgary residents are different. Explain why b. Give an example of confidence interval for ( ,-.) that would : (i) Strongly suggest that 2 (ii) Strongly suggest that 1SUz

Explanation / Answer

Given that,
mean(x)=5.1667
standard deviation , s.d1=1.6021
number(n1)=6
y(mean)=4.3333
standard deviation, s.d2 =0.5164
number(n2)=6
null, Ho: u1 = u2
alternate, H1: u1 > u2
level of significance, = 0.05
from standard normal table,right tailed t /2 =2.015
since our test is right-tailed
reject Ho, if to > 2.015
we use test statistic (t) = (x-y)/sqrt(s.d1^2/n1)+(s.d2^2/n2)
to =5.1667-4.3333/sqrt((2.56672/6)+(0.26667/6))
to =1.2128
| to | =1.2128
critical value
the value of |t | with min (n1-1, n2-1) i.e 5 d.f is 2.015
we got |to| = 1.21276 & | t | = 2.015
make decision
hence value of |to | < | t | and here we do not reject Ho
p-value:right tail - Ha : ( p > 1.2128 ) = 0.13969
hence value of p0.05 < 0.13969,here we do not reject Ho
ANSWERS
---------------
null, Ho: u1 = u2
alternate, H1: u1 > u2
test statistic: 1.2128
critical value: 2.015
decision: do not reject Ho
p-value: 0.13969
no evidence to conclude that private colleges is higher than mean out of
state tuition for public colleges