PLEASE READ THROUGH TO THE END. THANK YOU. AM NOT LOOKING FOR THE WHOLE ANSWER.

Question

PLEASE READ THROUGH TO THE END. THANK YOU.

AM NOT LOOKING FOR THE WHOLE ANSWER. I just need to know what values to substitute for j when I’m calculating. I know for i, I need to calculate by substituting from 2 through 11 i.e i=2 through 11. What about values for j, do I also substitute j=2 through 11, but it says j not equal to i.

PLEASE SEE MY PREVIOUS QUESTION BELOW AND THE url.

https://www.chegg.com/homework-help/A-First-Course-in-Probability-8th-edition-chapter-4-problem-15P-solution-9780136033134

Q: Chapter 4, Problem 15P

https://www.chegg.com/homework-help/A-First-Course-in-Probability-8th-edition-chapter-4-problem-15P-solution-9780136033134

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My Question pls.

CONFUSED PLS. What the values of j for each of the sumation in P(X=3); that is, how we arrive at values like 0.0270 (for the first expression when it contain j). That is (11/44+j * 12-j/56) * 10/56.What do I substitute for j to get rid of j and arrive at 0.0270. Also, how do I do this for the others like 0.0240 + .......+ 0.0024 in your solution to Q 15P Chapter 4. PLS HELP. Thank you.

SOMEONE RESPONDED INITIALLY, AND I'M STILL NOT CLEAR.

My question is from your statement: Now substituting values of i and j, where i not equal to j, we get =0.1435. I substituted i= 2 through 11. For j do I also substitute values for j as j=2 through 11? That is when substituting i=2 do I also substitute j=2, but it states i not equal to j, so I'm confused. Please solve for i=2 and j=?? to arrive at a value so I can use that to solve the other ones.

SOMEONE JUST SENT A COMMENT:

Anonymous posted 11 minutes ago

If i=2, then j=3,4,5,6,7,8,9,10,11 If i=3, then j=2,4,5,6,7,8,9,10,11 if i=4, then j=2,3,5,6,7,8,9,10,11 and so on.

Is this corrent. I will try substituting the and see the final answer. If any other help, please respond.

Thank you.

Explanation / Answer

Let the superset K be 2,3,4,5,6,7,8,9,10,11

Since, i is not equal to j , for every value of i we can find the values of j by removing the value of i from k.

Thus, for i=7 , the values of j are  2,3,4,5,6,8,9,10,11 and so on.

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