Is achieving a basic skill level related to the location of the school? The resu
ID: 3313907 • Letter: I
Question
Is achieving a basic skill level related to the location of the school? The results of a random sample of students by the location of school and the number of students achieving basic skill levels in three subjects is shown in the contingency table. At alpha equals =0.05, test the hypothesis that the variables are independent. Complete parts (a) through (d). Subject Location Reading Math Science Urban 43 47 131 SuburbanSuburban 65 70 67 (a) Identify the claim and state the null and alternative hypotheses. Upper H0: Skill level in a subject is location. Upper H Subscript aHa: Skill level in a subject is dependent on independent of location. The alternative hypothesis null hypothesis is the claim. (b) Determine the degrees of freedom, find the critical value, and identify the rejection region. What are the degrees of freedom? d.f.equals= 4 Find the critical value. chi Subscript 0 Superscript 220equals= nothing (Round to three decimal places as needed.)
Explanation / Answer
Given table data is as below
------------------------------------------------------------------
calculation formula for E table matrix
------------------------------------------------------------------
expected frequecies calculated by applying E - table matrix formulae
------------------------------------------------------------------
calculate chisquare test statistic using given observed frequencies, calculated expected frequencies from above
------------------------------------------------------------------
set up null vs alternative as
null, Ho: no relation b/w X and Y OR X and Y are independent
alternative, H1: exists a relation b/w X and Y OR X and Y are dependent
level of significance, = 0.05
from standard normal table, chi square value at right tailed, ^2 /2 =5.991
since our test is right tailed,reject Ho when ^2 o > 5.991
we use test statistic ^2 o = (Oi-Ei)^2/Ei
from the table , ^2 o = 28.895
critical value
the value of |^2 | at los 0.05 with d.f (r-1)(c-1)= ( 2 -1 ) * ( 3 - 1 ) = 1 * 2 = 2 is 5.991
we got | ^2| =28.895 & | ^2 | =5.991
make decision
hence value of | ^2 o | > | ^2 | and here we reject Ho
^2 p_value =0
ANSWERS
---------------
null, Ho: no relation b/w X and Y OR X and Y are independent
alternative, H1: exists a relation b/w X and Y OR X and Y are dependent
test statistic: 28.895
critical value: 5.991
p-value:0
decision: reject Ho
MATRIX col1 col2 col3 TOTALS row 1 43 47 131 221 row 2 65 70 67 202 TOTALS 108 117 198 N = 423Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.