QUESTION 7 X 112 64. Means10 68 12.4 Using the covariance table and means, solve

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QUESTION 7 X 112 64. Means10 68 12.4 Using the covariance table and means, solve for the following values. In the unstandardized regress on equation, y bo +b1'x, what is the value of bo? Round to two decima places. Also note, if you are using values prev ous estimated to estmate this vaue then do not use the answer you rounded to two decimal places, go back out to at least 4 decima places for the previousy estmated value. QUESTION 8 Y16 x11.2 64 … Z 5.28 230436 Using the covariance table and means, solve for the following values. In the unstandardized regress on equation, y b0 +b1z, wha: is the value of bo? Round to two decima places. Also note, if you are using values previcus estimated to es:imate this value then do not use the answer you rounded to two decimal places, go back out to at least 4 decima paces for the previcusy estimated value. QUESTION 9 Y16 X 112 4 5.28 2304 36 Means 10 68 12.4 Using the covariance table and means, solve for the following values. In the unstandardized regress on equation, x b0 +b1'z, what is the value of bo? Round to two decima places. Also note, if you are using values previous estimated to estimate this vaue then do not use the answer you rounded to two decimal places, go back out to at least 4 decma paces for the previousy estimated value. QUESTION 10 Y16 - X 11.2 64 2 5.28 23.04 36 Means 10 8 Using the covariance table and means, solve for the following values. in the r standardized egresso equation x b0 + b1 y what s the vaue of b0? Round to two decmai places. Aso note, places, go backout to at least 4 decimal paces for the prev ousy estimated value. 12.4 you are usng vaues previous estimated to est ate this value then do not use the answer you ounded to two dec mal QUESTION 11 16 X 112 64 Z 5.28 2304 36 Meons 10 68 Using the covariance table and means, solve for the following vaues. in the standardized egresson equation, z = 60·01 , w t atthe va e of b0 Round to two dec m a piaces. Also note if you are using values previous estimated to est places, go back out to at least 4 decma paces for the previousy estimated value. ate ths vaue ten do not use the answer you ounded to two dec a

Explanation / Answer

reading the standard covariance table, we get

var(Y)= 16

var(X)= 64

var (Z) = 36

cov(XY) = 11.2

cov(XZ) = 23.04

cov(YZ)= 5.28

Ques 7

y = b0 + b1*x

b1= cov(XY) / var(X) = 11.2/64 = 0.175

it will pass through means (uy, ux) that is means of y and means of X

so uy = b0 + b1*(ux)

=> 10 = b0 + 0.175*(6.8)

so b0 = 8.81

Ques 8

y = b0 +b1*Z

b1= cov(YZ)/var(z) = 5.28/36 = 0.1467

it will pass through means (uy,uz) that is means of y and z

uy = b0 +b1*uz

10 = b0 + 0.1467*12.4

b0 = 8.18

ques 9

x = b0 +b1*Z

b1= cov(XZ)/var(z) = 23.04/36 = 0.64

it will pass through means (ux,uz) that is means of x and z

ux = b0 +b1*uz

6.8 = b0 + 0.64*12.4

b0 = -1.14

Ques 10

x = b0 +b1*y

b1= cov(XY)/var(Y) = 11.2/16 = 0.7

it will pass through means (ux,uy) that is means of x and y

ux = b0 +b1*uy

6.8 = b0 + 0.7*10

b0 = -0.2

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