[Q11e: Only answer if you ABSOLUTELY know how to solve AND the answers match up
ID: 3313048 • Letter: #
Question
[Q11e: Only answer if you ABSOLUTELY know how to solve AND the answers match up ((tired of getting wrong replies.) So, please make sure you’re really certain. [It’s appreciated.])
Really Explain EACH STEP, including any formulas you used (& how to use the formula), and explain how to compute with a TI-84 preferably/when possible.]
NO JUST POSTING THE ANSWER WITH NO EXPLANATION/ NO CONVINCING EXPLANATION, I WILL ASSUME IT'S WRONG, AS HAS BEEN THE CASE BEFORE. IF YOU'RE THIS TYPE, MOVE ON.
Question
Suppose that a researcher studying the weight of female college athletes wants to predict the weights based on height, measured in inches, and the percentage of body fat of an athlete. The researcher calculates the regression equation as (weight) = 4.037*(height) + 0.881*(percent body fat) - 81.271. If a female athlete is 60.376 inches tall, has a 20.865 percentage of body fat, and a weight of 219.105. What is the residual?
Question options:
1)
2)
3)
4)
5)
1)
43.0152)
38.2563)
-38.2564)
120.4735)
We do not know the observations in the data set, so we cannot answer that question.Explanation / Answer
The fitted regression model is
weight) = 4.037*(height) + 0.881*(percent body fat) - 81.271.
If a female athlete is 60.376 inches tall, has a 20.865 percentage of body fat,
Then
weight) = 4.037*(60.376) + 0.881*(20.865) - 81.271.
weight=180.849
Actual weight is 219.105
residual =actual-predicted =219.105-180.849=38.256
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