d. 0.06 e 1.6 22. In order to estimate the average numbers of miles that student
ID: 3312156 • Letter: D
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d. 0.06 e 1.6 22. In order to estimate the average numbers of miles that students who live off-campus commate to e every day the following statistics were given: n-so, x-521, and s = 248. The point estimate of the true population mean is: a. 1.96 b. 2.10 c. 5.21 d. 7.07 e. 2.78 23. A 90% confidence interval estimate of the population mean can be interpreted to mean if we repeatedly draw samples of the same size from the same population, 90% of the a. values of the sample means ž will result in a confidence interval that includes the population mean there is a 90% probability that the population mean win lie between the lower confidence limit (LCL) and the upper confidence limit (UCL) we are 90% confident that we have selected a sample whose range of values does not contain the population mean b, , d, we are 90% confident that 10% the values of the sample means x will result in a confidence interval that includes the population mean . e, 90% of the values of the sample means x are equal to the population mean . 24. Indeveloping an interval estimatefora population mean, the population standard deviation was s. The interval estimate was 40.52 ± 3.24. Had equaled 16, the interval estimate would be: a. 40.52±11.24 40.52±6.48 81.04 ±11.24 b. c, d. 48.52 ±11.24 e, 81.04±6.48 25. The lower limit of a confidence interval at the 95% level of confidence for the population proportion if a sample of size 100 had 30 successes is: a. 0.3898 b. 0.3041 e. 0.2959 d. 0.2102 e. 0.3126 26, when estimating a population mean , where the population standard deviation is known, we can: a. define the limits of an interval estimate of as z-nofJn c. choose a smaller z value, construct a narrower confidence interval, and achieve a higher d. choose a larger z value, construct a wider confidence interval, and achieve a lower define the limits of an interval estimate of asta/2-5 /n confidence level confidence levelExplanation / Answer
22) Point estimate for population mean is sample mean is 5.21.
because sample mean is an unbiased estimate of population mean. Thus the answer is option (c).
23) The answer is option (d).
24) answer is option (b)... dividing the margin of error by 8 and multiplying it by 16 we get 6.48.
26) answer is option (a).
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