Problem4 (5 pts, 0.5pt for each correctly filled cell. The data are given below.

Question

Problem4 (5 pts, 0.5pt for each correctly filled cell. The data are given below. Using the given data fill up the table below, except for p-value and F critical. p-value ANOVA Source of Variation Between Groups Within Groups Total Complete filling up the table using one of the options below (1) F= 2.89 p-value = 0.1223 F-critical=12.514 (2) F= 0.89 p-value = 0.5329 F-critical= 0.514 (3) F=1.33 p-value = 0.3318 F-critical=5.143 (4) F= 2.33 p-value = 0.1299 F-critical=10.562 (5) F= 0.75 p-value = 0.5223 F-critical=0.514 (6) F=2.25 p-value = 0.0381 F-critical=19.562

Explanation / Answer

Ans:

F=1.33,

p-value=FDIST(1.33,2,6)=0.3318,

Fcritical=FINV(0.05,2,6)=5.143

Option 3 is correct.

calculations:

SST=126-(30^2/9)=26

SSTR(between)=(12^2+6^2+12^2)/3-(30^2/9)=8

SSE(within)=26-8=18

df(between)=3-1=2

df(within)=9-3=6

MS=SS/df

F=MS(between)/MS(within)

x A B C 3 1 4 2 2 5 7 3 3 Total= 12 6 12 overall sum 30 x^2 A B C 9 1 16 4 4 25 49 9 9 overall sum 126 SST= 26 SSTR= 8 SSE= 18 SS df MS F Fcritical p-value Between 8 2 4 1.33 5.143 0.3318 Within 18 6 3 Total 26 8

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