Plz work all the steps without using computer. Thank you Plz work all the steps

Question

Plz work all the steps without using computer. Thank you Plz work all the steps without using computer. Thank you 5. To judge the effectiveness of an advertising campaign for a certain brand of potato chip, a random sample of 500 supermarket receipts was taken during the week before the ad campaign began, and 65 of them showed a purchase of the potato chips. Another random sam- ple of 500 receipts was taken during the week after the campaign ended, and 92 of them showed a potato chip purchase. Find a 99% confidence interval for the

Explanation / Answer

Sol:

sample proportion=p1^=x1/n1=65/500=0.13

sample proportion=p2^=x2/n2=92/500=0.184

z crit for 99%=2.576

99% confidence interval for difference in proportions=

(p1^-p2^)+-zritsqrt(p1^(1-p1^)/n1+p2^(1-p2^)/n2)

=(0.13-0.184)+-2.576sqrt(0.13(1-0.13)/500+0.184(1-0.184)/500))

=-0.054+-0.0591

=-0.054-0.0591,-0.054+0.0591

=-0.1131,0.0051

lower limit=-0.1131

upper limit=0.0051

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