These questions use R. 1. Enter the following values into a data vector named te

Question

These questions use R.

1. Enter the following values into a data vector named testdata: 45.4 44.2 36.8 35.1 39.0 60.0 47.4 41.1 45.8 35.6 Calculate the difference between the 2nd and 7th entries of this vector using only reference indices. 2. 3. Calculate the median of testdata. . Sort the values in this data vector from highest to lowest, and save the sorted version as a 5. 6. 7. vector named sortHL.testdata. What does sortHLtestdata[-4] do? What does testdatal-c(2,7,9)] do? Why do you think the c() function necessary in the previous question?

Explanation / Answer

1] enter the data vector named in testdata

testdata=c(45.4,44.2,36.8,35.1,39.0,60.0,47.4,41.1,45.8,35.6)
testdata

2]   diff=testdata[2]-testdata[7]
diff
[1] -3.2

we find the difference between the 2nd and 7th entries of the vector above is -3.2

3] in finding median in 2 methods

1st is we put in r

median(testdata)

[1] 42.65

and 2nd method is

just put in r

summary(testdata)

we get hole out put

> summary(testdata)
Min. 1st Qu. Median Mean 3rd Qu. Max.
35.10 37.35 42.65 43.04 45.70 60.00

so, we get median is 42.65

4] sorting the data in to higest to lowest

we pur in r commad

sorthHL.testdata=sort.list(testdata, partial = NULL, na.last = TRUE, decreasing = TRUE, method ="radix")

we get r out put is

> sorthHL.testdata
[1] 6 7 9 1 2 8 5 3 10 4

5]  sorthHL.testdata[-4]
[1] 6 7 9 2 8 5 3 10 4

this command removing 4th entries in sorth.testdata

so we get ouput in r is,  6 7 9 2 8 5 3 10 4

6] sorthHL.testdata[-c(2,7,9)]
[1] 6 9 1 2 8 3 4

this command removing 2nd, 7th and 9th entries at one time

and we get out in r is, 6 9 1 2 8 3 4

7] yes,

"c" stands for "combine". You are combining items together into one vector

c() is necessary because c() function used in combing the values, so that's why this is needed.

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