please explain how -.841 was calculated. and where did the .-841=(x-575)/5 equat
ID: 3309771 • Letter: P
Question
please explain how -.841 was calculated. and where did the .-841=(x-575)/5 equation come from??
The diameter of an automobile tire is normally distributed with a mean of 575 mm and a standard deviation of 5 mm 1. What is the probability that a randomly selected tire has a diameter between 575 and 579 mm? a. x-x Z575= (575-575)/5-0 Z579-(579-575)/5 = .80 From the z-table we see that 0, the mean of the standard normal distribution has a cumulative probability of .50 For.8, we find the cumulative probability to be.7881. Thus, the probability of finding a tire at random, with diameters between 575 and 579 is .7881-.50 = .2881 b. 80% of tires have diameters above what value? Zip=2)--841 ????How -841 = (x-575)/5 4.205 (x-575) 570.79mm =Explanation / Answer
The z value for 0.2 can be calculated by looking at the z value for 0.8 from the normal distribution table and negating it. we see that the closest p is 0.7995 in the table which gives us the z of 0.84 and the answer is negative of it which is -0.84
z is given as (x-mean)/s statistically, thus we get .-841=(x-575)/5
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