The mean height of American women is about 63.4 inches and the stan- dard deviat

Question

The mean height of American women is about 63.4 inches and the stan- dard deviation is about 1.8 inches. The mean height of American men is about 66.6 inches with a standard deviation of 3.3 inches. The correlation between the heights of husbands and wives is about 0.4 (a) We want to predict the height of the husband whose wife is 63.4 inches tall. The slope of the appro (a) 20.1088 48.8679 priate regression line is (c) 0.7333 b) 0.2182 (b) The intercept of the appropriate regression line is b. 48.8679 c. 20.1088 a. 0.218:2 0.7333 (c) The predicted value of husbands height when wife's height is 63.4 inches 1s a. 64.1333 b. 66.60002 c. 1275.63122 (d) There are two data points, x-wife's height-63 with husband's height- 70.7067, and another pair with x2-67.4 and y2-78.33322 If you use the regression line computed earlier then i. The residual at x2 is equal to the residual at x1 ii. The residual at x2 is smaller than the residual at xl i. The residual at x2 is larger than the residual ii at xl (e) The regression line that you found out in this problem is 1. The regression line of mens's heights on women's heights ii. The regression line of womens's heights on men's heights 111. lt same does not matter both are the

Explanation / Answer

a) slope b1=r*Sy/Sx =0.4*3.3/1.8=0.7333

option C is correct

b)

intercept bo =Ybar-b1*Xbar =66.6-0.7333*63.4=20.1088

option C

c)

predicted value of men height =20.1088+0.7333*63.4=66.60002

option B

d) residual at x2 =78.33322-(20.1088+0.7333*67.4)=8.8

residual at x1 =70.7067-(20.1088+0.7333*63)=4.4

from above option (iii) is correct

e) option (i) : the regression line of men's heights on women;s heights

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