2.5.034.XP My Notes Ask Your Teachd express subway train passes through an under

Question

2.5.034.XP My Notes Ask Your Teachd express subway train passes through an underground station. It enters at t-O with an initial velocity of 23.0 m/s and decelerates at a rate of 0.150 m/s? as it goes through The station in 210 m long (a) How long is the nose of the train in the station? (b) How fast is it going when the nose leaves the station? e) Ir the train is 130 m long, at what time t does the end of the train leave the station? (d) What is the velocity of the end of the train as it leaves? m/s m/s

Explanation / Answer

a]

d = 210 m

v2 = u2 + 2ad

=> v = [232 - 2(0.15)(210)]1/2 = 21.587 m/s

this is how fast it going when it leaves the station [answer - b]

now use v = u + at

=> 21.587 = 23 - 0.15t

=> t = 9.42 s

this is how long the nose of the train is in the station [answer - a]

c]

again use,

v2 = u2 + 2ad

=> v = [21.5872 - 2(0.15)(130)]1/2 = 20.66 m/s

this is the velocity of the end of the train as it leaves the station [answer d]

v = u + at

20.66 = 21.587 - (0.15)t

=> t = 6.154s.

this is the time after the nose leaves the station when the end of the train leave. [answer c].

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