If a positive red puck is originally placed direclty south to a positive black p

Question

If a positive red puck is originally placed direclty south to a positive black puck, and then the black puck is changed to negative, What happens to the direction of the electrostatic force?

C. The electrostatic force on the black negative puck is not changing its direction because this force is applied by the red puck.

Two positive point charges Q and 2Q are separated by a distance R. The charge Q experiences an electrostatic force of magnitude F. What is the magnitude of the force on the charge 2Q?

Four point charges of equal magnitude but with varying signs are arranged on three of the corners and at the center of the square of side d as shown. Which of the arrows shown represents the net force acting on the center charge? (2 points)

A. The electrostatic force on the black negative puck is oriented down, toward the red positive charge: the two charges attract each other. B. The electrostatic force on the red positive puck is not changing its direction because only the charge on the black puck was changed.

C. The electrostatic force on the black negative puck is not changing its direction because this force is applied by the red puck.

Two positive point charges Q and 2Q are separated by a distance R. The charge Q experiences an electrostatic force of magnitude F. What is the magnitude of the force on the charge 2Q?

A. 4F B. 2F C. F D. F/2 E. F/4

Four point charges of equal magnitude but with varying signs are arranged on three of the corners and at the center of the square of side d as shown. Which of the arrows shown represents the net force acting on the center charge? (2 points)

A. A B. B C. C D. D E. none of the above

Explanation / Answer

net force on the center = 2kQ^2/d^2 <------magnitude
So, the arrow sown as A represents the net force on the central particle..

Answer is: "A"

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