pertta Help HW 5 Begin Date: 221/2018 120100 AM-Dee Date:3/1/2018 11:59.00 PM En
ID: 3309075 • Letter: P
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pertta Help HW 5 Begin Date: 221/2018 120100 AM-Dee Date:3/1/2018 11:59.00 PM End Date:5/5/2018 11:39.00 PM (6%) Problem 18: An ideal pendulum of length L-1.3m supports a mass of m- 0.5 kg Initially the pendalura is lifted sach that it makes an angle of 8- 28 degrees with respect to the vertical Otheespertta.com 50% Part (a) When the pendulum is released from rest, what is the mutimum speed, v-ams, the mass reaches? Grade Sammary Potential 1004 sin0 cosO cotan asin acos atan0 acotan sinb0 cos tan cotan0 Degrees ORadians Hant Feedback:deduction per feedback · 50% Part (b) Does increasing the mass at the end increase the maximum speed?Explanation / Answer
a) m g h = 1/2 m v2
1/2 m v2 = m g L (1 - cos theta)
v = sqrt [2 g L (1 - cos theta)]
v = sqrt [2 * 9.8 * 1.3 (1 - cos 28)]
maximum speed v = 1.73 m/s
b) No
[speed does not independent on mass]
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